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Flat earthers and other retards will be banned from this sub mercilessly.

You wouldn't want to hear my theories, anyways. They involve things like human beings and not space-magic from outer space.

In light of not being a globe-guy now, I often wonder what the Carrington Event was. If man made, or natural. If the latter, what force caused it. The sun, or something else?

> Flat earthers and other retards will be banned from this sub mercilessly. You wouldn't want to hear my theories, anyways. They involve things like human beings and not space-magic from outer space. In light of not being a globe-guy now, I often wonder what the *Carrington Event* was. If man made, or natural. If the latter, what force caused it. The sun, or something else?

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[–] • 0 pt

You edited your comment and added the paper after i made mine, so I didn't see it.

What exactly are you trying to solve here? Are you trying to solve for the distance down the curve, that the hypothetical mountain that is 200 miles away, would be?

My point is that you wouldn't be able to see said mountain because it would be too far down the curve of the earth. According to globe earth ttheory.

[–] • 0 pt (edited )

I used basic geometry and algebra to prove that you can see 230 miles from a height of 6.8 miles on a sphere that is 3,900 miles in radius and around 25k miles in circumference.

The point you are looking at isn't "68 miles down", it's a gradual descent from 6.8 miles above the ground to ground level on the sphere 230 miles out (look at the picture in the PDF).

[–] • 0 pt

Fascinating. I am still curious about how the angle of the curve is entirely imperceptible. Though I suppose the explanation i "it's not stark enough to notice". But even a 3.6 degree decline would seemingly be noticable at some level since, as your sight progresses up towards the horizon from the ground immediately beneath you, the ground is dropping by miles and miles.

I would be interested to hear your explanation about the ship sinking past the horizon and then being re-viewable by zooming in from the same viewpoint. I have heard many a globe earther use it as an example for the curve, but they can never explain why one could zoom in from the same viewpoint and see past the curve.

[–] • 0 pt (edited )

I don't think you understand the geometry. Where are you getting "3.6 degree decline" from? That degree of decline is going to depend on other variables. You are mashing up different concepts from trigonometry, algebra, and geometry in a nonsensical manner. Post the math.

1) The earth is an oblate spheroid, but is close enough to a sphere. 2) Cutting a sphere through the midpoint gives you a circle. 3) You measure viewing distance by using a right triangle and solving for a leg of that triangle. 4) The hypotenuse is the radius of the circle + the height above ground, whether that's 5 feet or 6.8 miles 5) Leg 1 of the right triangle is the radius of the circle (which takes you to the point on the circle at the maximum possible viewable distance). 6) You can then use the Pythagorean Theorem to calculate the viewable distance that extends from the hypotenuse above the circle to the most distant point on the circle that is viewable.

I would be interested to hear your explanation about the ship sinking past the horizon and then being re-viewable by zooming in from the same viewpoint.

This is bullshit. If someone was actually able to do this, it was probably because the seas calmed down from 6 foot waves to 1 foot waves, and/or the ship dumped ballast, not because "zooming in" magically made the ship observable.