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Flat earthers and other retards will be banned from this sub mercilessly.

You wouldn't want to hear my theories, anyways. They involve things like human beings and not space-magic from outer space.

In light of not being a globe-guy now, I often wonder what the Carrington Event was. If man made, or natural. If the latter, what force caused it. The sun, or something else?

> Flat earthers and other retards will be banned from this sub mercilessly. You wouldn't want to hear my theories, anyways. They involve things like human beings and not space-magic from outer space. In light of not being a globe-guy now, I often wonder what the *Carrington Event* was. If man made, or natural. If the latter, what force caused it. The sun, or something else?

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[–] 0 pt

Yeah you have to piss me off with something really stupid that can be disproven with grade school math and a pair of eyes, you know, like flat earth theory.

[–] 2 pts

You can disprove globe earth with basic math, too.

Circumference around equator = ~24,100 miles Extent of viewing distance at 36,000 feet = ~211 miles Formula for circumference of circle = C = 2πr Formula for radius can be derrived = r = C / 2π Radius of Earth given aforementioned circumference = r = 24,100 / 2π = ~3836 miles

You can see a mountain 200 miles away from 36,000 feet (curising altitude of most commercial airliners) 200 miles is ~0.83% of the circumference of the Earth If you travel half the circumference of a cirlc,e you've traveled the entire radius Thus, 200 miles, or ~0.83% of the circumference would be ~1.66% of the radius 3836 Miles * 1.66% = ~63 Miles

Therefore, the mountain you're looking at that is 200 miles away is, allegedly, 63 Miles DOWN the curve of the earth.

Now I wait for the response about "but muh light bending correlois effect!"

You can see a ship sail "down the curve" and watch is descend into the horizon. Makes sense with globe earth theory, but one can take a telescope, or a powerful camera like a P900, and zoom in from the same viewpoint, and see the ship again. How can that be if the light has already bent along the curve of the earth before the photons have collided with your retinas?

The telescope/camera is receiving the exact same photons of light, then magnifying a small subsection of it. How would that magnification, post-bending, affect the light bending along the curve of the earth?

... You can ban me now.

[–] 2 pts

Perfect reply! Then there's this...

https://pic8.co/sh/Zt77ve.jpg

[–] 2 pts

Nice pic, thanks for sharing!

[–] 1 pt (edited )

Correct, Earth is not a globe. It is an oblate spheroid.

If you travel half the circumference of a cirlc,e you've traveled the entire radius Thus, 200 miles, or ~0.83% of the circumference would be ~1.66% of the radius 3836 Miles * 1.66% = ~63 Miles

What? The radius of the earth is about 3,900 miles. The circumference is about 25,000 miles. 200 miles is 0.8% of the circumference and about 5% of the radius. You fail grade school math.

Therefore, the mountain you're looking at that is 200 miles away is, allegedly, 63 Miles DOWN the curve of the earth.

You need to revise your maths.

https://sites.math.washington.edu/~conroy/m120-general/horizon.pdf

Hypotenuse: R+height of plane "h" = 3,900 + 6.8 = 3,906.8 miles Leg 1: R or 3,900 miles Leg 2: L (the variable we need to solve for, the visible distance to the horizon with a smooth globe shaped earth from a plane 6.8 miles up)

3,906.8 = √(L2 + 3,9002 ) Square both sides gives us... 15263086.24 = (L2 + 3,9002 ) We square 3,900 to get... 15263086.24 = (L2 + 15210000) Subtracting 15210000 from both sides gives us... 53086.24 = L2 Taking the square root of 53086.24 gives us... L = 230.404513844672757 miles

[–] 0 pt

What? The radius of the earth is about 3,900 miles. The circumference is about 25,000 miles. 200 miles is 0.8% of the circumference and about 5% of the radius.

Re-read. Traveling 200 miles along the circumference means you've traveled 0.8% of the circumference which means youve' traveled ~1.6% of the distance of the radius, being about 60 miles.

You fail grade school math.