Or you're blocked. On the context of the mentioned thread I really didn't care enough to really answer, but here; >A number is Fibonacci if and only if one or both of (5*n2 + 4) or (5*n2 – 4) is a perfect square. >>using the above we assume that the function bool IsFib(int) is defined and implemented as well as any other necessary libraries and or functions Assuming S is a string array drawn from a string which contains the text where each element of S corresponds to a word from the source text (string). Example; >We Are All Bears. Would have S be; S[0] = We S[1] = Are S[2] = All S[3] = Bears We can do; >the below assumes a returned empty string is checked for and ignored. for (int i = 0, i < S.size() - 1, i++) return IsFib(i+1) ? S[i] : ""; // i+1 passed because it's assumed most people aren't computers and count the first word in a text as word 1, and not word 0 Just because you're a nigger does not mean I am. e; I also didn't see your reply in the Fib. thread, so I didn't care either way about your totally ebin reply. This is why you're blocked, you're a tryhard untermensch faggot. You aren't worth the time. Even (((Based_Semen))) replies better than you could ever hope to and he's the base form of a jew owned NPC if not a jew shill account. Though again, don't care. ee; Ternary operator unncessary. Could just if and return the index / word if true. Whatever, you're a nigger. C++ is best language, C "better" but not worth the headache.