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[–] 0 pt

A quick calculation to check feasibility:

Static propeller thrust T = ³√(P² ✕ η² ✕ Η² ✕ π ✕ (d²/2) ✕ ρ)

Where:

T is thrust in Newtons P is power of motor in Watts η is propeller efficiency, 1 is perfect Η is motor efficiency, 1 is perfect d is propeller diameter in meters ρ is air density in kg/m³

Known numbers:

P = 350 W, or 175 W per rotor (a simplification, but close enough) d = 1.2 m ρ = 0.013 kg/m³ at Mars' surface

Using typical efficiencies for propellers and motors:

η = 0.75 Η = 0.9

Mass of helicopter in Mars' gravity is 0.68 kg.

Using these numbers for one rotor:

T = ³√(30625 ✕ 0.56 ✕ 0.81 ✕ 3.14 ✕ 0.72 ✕ 0.013) ≈ 7.4 N

7.4 N is around 0.75 kg of thrust for a single rotor - more than the helicopter's weight on Mars. So with both rotors it'll have more than enough thrust to fly there.

[–] 0 pt

Where did you copy that from?

[–] 0 pt

Beyond the initial formula, the calculation is mine. It's basic mathematics.