According to the bullshit earth curvature you assuredly believe in, there would be over 652,000 feet or 123 miles of curvature between you and the other observer 1,000 miles away. So tell me again how this would be accurate and while you’re at it go ahead and measure the “angle” of any object in the sky with any accuracy. Oh wait, you can’t, won’t, never have, and never will.
According to the bullshit earth curvature you assuredly believe in, there would be over 652,000 feet or 123 miles of curvature between you and the other observer 1,000 miles away.
Why are you assuming that the 1,000 miles is measured at the surface and not by a straight line between the two points? Even a high school flunky would know that calculating the legs of a triangle requires, well, a triangle.
Yeah. 1,000 miles on the SURFACE of the earth should result in 123 miles of curvature on that surface.
Yeah. 1,000 miles on the SURFACE of the earth should result in 123 miles of curvature on that surface.
Exactly. For example, one observer is at Palomar Observatory in California and the other is at the Leander McCormick Observatory in Virginia. The distance on the surface of the Earth is 2,160.24 miles, but a straight line through the Earth between those two points is 2,133.54 miles. Observers at those two observatories observe a difference of 0.512 degrees between the apparent position of the Moon as measured from the line running between them through the Earth.
d = b / (2 * tan (a / 2))
d = 2,133.54 / (2 * tan (0.512 / 2))
d = 2,133.54 / (2 * tan (0.256)
d = 2,133.54 / (2 * 0.0044681)
d = 2,133.54 / (2 * 0.0044681)
d = 2,133.54 / 0.0089362
d = 238,752
There's your distance to the Moon.
(post is archived)