This is not a support of Q. This is a fact. I think the only frauds are Flynn and Wood. Just saying. Very unpopular stance I know. But here's the thing. Flynn was fired 24 days into the Trump admin. Then he stayed tied up the entire time. Coincidence? Probably not. I've never trusted Flynn. And Wood? Wood led the legal team for Ramsey. We should all pay attention to that given what we know now. Flynn openly supported Q and now he's like, that shit is disinformation. Ummm, okay. More likely that Flynn is disinformation. Especially since he hasn't given anyone in this fucking country a credible piece of info. Period. He can shill all he wants. If Q is fake and gay then Flynn can set it straight. Will he? No. He's a fucking traitor and he knows it.
https://www.nytimes.com/2021/02/06/us/politics/michael-flynn-qanon.html
Flynn wasn't talking about Q.
This article is so confusing. Is the ultimate goal of the article to say that the left created a disinformation campaign about Q but Q was useful. Or is Flynn saying the movement was disinformation?
Whoever started posting the sound clip is ignoring a lot of things in order to make it seem like Flynn is referring to Q followers.
Qanon started out as a hashtag that helped Q followers network information. The MSM started using the label to refer to Q followers early on, and Q posted many links to those articles, showing how they were trying to make us out as a group of crazy conspiracy theorists. Q eventually warned us to not refer to ourselves as Qanon because of this. Before Q did this, Trump, Flynn, and many others gave support to us using that label. Flynn is disavowing the label and stating that he thinks the CIA (via their MSM) used it as a disinfo campaign, which is exactly what happened. This is part of information warfare, which Flynn knows a lot about. He's using plausible deniability of any knowledge of Q in order to protect the Q operation.
At the end of the original clip that I heard (not included in the one in the OP's link), Wood points out that he still supports Q.
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