Welcome • User Guide
ToS • Privacy • Canary
Donate • Bugs • License

©2026 Poal.co

497

For example if one player has 9:4 odds of winning and another has 5:2 that means that out of 13 results the first player will win 9 times or 4 times and out of 7 results the second player will win 5 times or 2 times? Which would then mean 9/13 -or- 4/13 % chance and 5/7 -or- 2/7 % chance respectively?

For example if one player has 9:4 odds of winning and another has 5:2 that means that out of 13 results the first player will win 9 times or 4 times and out of 7 results the second player will win 5 times or 2 times? Which would then mean 9/13 -or- 4/13 % chance and 5/7 -or- 2/7 % chance respectively?

(post is archived)

You are currently inside a comment thread.
Click here to see all the comments (4).
[–] • 0 pt (edited )

As I understand it, 1:1 (one to one) would be 50/50, like heads or tail in a coin toss.

A 2:1 (two to one) chance of winning would mean the chance of a win is twice the chance of a loss.

Two to one expressed in percentage would be: we have three parts (2+1) so 100 divided by 3 we get 33.3%. Multiply by your odds that is 66.6% win vs 33.3% lose chance.

Or, out of three times there will be two wins, one loss.