Welcome • User Guide
ToS • Privacy • Canary
Donate • Bugs • License

©2026 Poal.co

931

For example if one player has 9:4 odds of winning and another has 5:2 that means that out of 13 results the first player will win 9 times or 4 times and out of 7 results the second player will win 5 times or 2 times? Which would then mean 9/13 -or- 4/13 % chance and 5/7 -or- 2/7 % chance respectively?

For example if one player has 9:4 odds of winning and another has 5:2 that means that out of 13 results the first player will win 9 times or 4 times and out of 7 results the second player will win 5 times or 2 times? Which would then mean 9/13 -or- 4/13 % chance and 5/7 -or- 2/7 % chance respectively?

(post is archived)

[–] • 5 pts

I think this is what you are looking for:

https://88probett.com/horse-race-betting-101-understanding-how-to-read-horse-racing-odds/

The important part is that the betting odds are not the same as the actual odds of winning. It just reflects where people are placing their bets, so that the house can entice more bettors, but still have their risk evenly spread so they'll make a profit no matter who wins.

[–] • 0 pt

So does that mean the first person to place the bet is looking at 0:0 odds?

[–] • 0 pt

No, they have starting odds, and change as needed. Or most local bookies just follow Vegas odds.

[–] • 0 pt (edited )

As I understand it, 1:1 (one to one) would be 50/50, like heads or tail in a coin toss.

A 2:1 (two to one) chance of winning would mean the chance of a win is twice the chance of a loss.

Two to one expressed in percentage would be: we have three parts (2+1) so 100 divided by 3 we get 33.3%. Multiply by your odds that is 66.6% win vs 33.3% lose chance.

Or, out of three times there will be two wins, one loss.