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587

λmax= 2.8977729×103mK 193.0

=15014.367357513 nanometers

https://www.vcalc.com/wiki/sspickle/Blackbody+wavelength+from+Temperature

But when I do it on the calculator I end up with 150.14 and not unless I go 105 I get the right number.

eta: I'm asking\ because I'm going to show climate retards that co2 absorbs only low energy photons and I can't be fucking up the equation, Thanks

λmax= 2.8977729×10^3mK 193.0 =15014.367357513 nanometers https://www.vcalc.com/wiki/sspickle/Blackbody+wavelength+from+Temperature But when I do it on the calculator I end up with 150.14 and not unless I go 10^5 I get the right number. eta: I'm asking\ because I'm going to show climate retards that co2 absorbs only low energy photons and I can't be fucking up the equation, Thanks

(post is archived)

[–] 1 pt

Actually no, I am trying to find the wave emitted. Co2 only absorbs the 15µm and based on the above, that's 193K . Too cold for the earth but not the atmosphere.

[–] 4 pts (edited )

The way CO2 acts as a greenhouse gas is by absorbing energy as I described and then sharing that energy out in the three ways I described.

Black body radiation isn’t how it transfers energy to the atoms around it. It’s done through inelastic collisions and emission of longer wavelength relaxation photons that are absorbed by other bonds types. The black body temperature of the atoms is just too low be a meaningful contribution to energy transfer to the surroundings.

Edit: stupid auto correct

[–] 2 pts

>Black body radiation isn’t how it transfers energy to the atoms around it.

I'm aware. The point of this exercise is to show the temperatures involved for emitting wavelengths that co2 is able to intercept aren't from the surface. Too warm to produce 15µ.

[–] 3 pts

Your argument makes no sense.