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730

λmax= 2.8977729×103mK 193.0

=15014.367357513 nanometers

https://www.vcalc.com/wiki/sspickle/Blackbody+wavelength+from+Temperature

But when I do it on the calculator I end up with 150.14 and not unless I go 105 I get the right number.

eta: I'm asking\ because I'm going to show climate retards that co2 absorbs only low energy photons and I can't be fucking up the equation, Thanks

λmax= 2.8977729×10^3mK 193.0 =15014.367357513 nanometers https://www.vcalc.com/wiki/sspickle/Blackbody+wavelength+from+Temperature But when I do it on the calculator I end up with 150.14 and not unless I go 10^5 I get the right number. eta: I'm asking\ because I'm going to show climate retards that co2 absorbs only low energy photons and I can't be fucking up the equation, Thanks

(post is archived)

[–] 9 pts

I’m a Physical Chemist. You’re using the wrong equation.

The equation you’re using is for calculating the wavelength of the photon EMITTED based on the temperature of the atom it relaxes. i.e. Why does human body temp show up as infrared wavelengths?

What you’re trying to talk about is the wavelength ABSORBED by the atom. You need the equation found here.

https://byjus.com/photon-energy-formula/

Now. Take the bond energy of a Carbon/Oxygen Double Bond. That’s the only kind that exists in CO2. Use that energy for the energy in the equation above.

Make sure to do a dimensional analysis though. The bond energy is likely in kJ/mol. So you’ll need to covert it to the energy of a single atom’s double bond by dividing by Avogadro’s number. Then putting it into the energy equation above. Solve that equation for Lambda to get wavelength.

Another thing to keep in mind. When a molecule absorbs a photon it can do a few things. It can transition electrons and then relax them and remit the photon. It can transition electrons, then relax a little, keeping some energy, then emit the rest as a photon. It can transition electrons, then relax by wiggling and rotating keeping it all.

In the last case it makes the atom “hotter”. Well then it runs into other gas atoms and can collide with them. It may even give some of its energy to them. Also making them a little “hotter” and itself a little “cooler”. This is exactly how your microwave works to heat your food.

[–] 1 pt

Actually no, I am trying to find the wave emitted. Co2 only absorbs the 15µm and based on the above, that's 193K . Too cold for the earth but not the atmosphere.

[–] 4 pts (edited )

The way CO2 acts as a greenhouse gas is by absorbing energy as I described and then sharing that energy out in the three ways I described.

Black body radiation isn’t how it transfers energy to the atoms around it. It’s done through inelastic collisions and emission of longer wavelength relaxation photons that are absorbed by other bonds types. The black body temperature of the atoms is just too low be a meaningful contribution to energy transfer to the surroundings.

Edit: stupid auto correct

[–] 2 pts

>Black body radiation isn’t how it transfers energy to the atoms around it.

I'm aware. The point of this exercise is to show the temperatures involved for emitting wavelengths that co2 is able to intercept aren't from the surface. Too warm to produce 15µ.